What number should be added to the polynomial $x^2-5 x+4$ so that 3 is the zero of the polynomial?
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What number should be added to the polynomial $x^2-5 x+4$ so that 3 is the zero of the polynomial?

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SOLUTION —

Let $k$ be the number to be added to the given polynomial. Then the polynomial becomes $x^2-5 x+(4+k)$.

As 3 is the zero of the polynomial, we get :

$\begin{aligned}& & (3)^2-5(3)+(4+k) & =0 \\\Rightarrow & & (4+k) & =15-9 \\\Rightarrow & & 4+k & =6 \\\Rightarrow & & k & =2\end{aligned}$

Thus, 2 is to be added to the polynomial.

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