SOLUTION —
$\sqrt{360}=\sqrt{2 \times 2 \times 2 \times 3 \times 5}=6 \sqrt{10}$
If we multiply $6 \sqrt{10}$ with $\sqrt{10}$ and 1 .
We get, $6 \sqrt{10} \times \sqrt{10} \times 1=60$
Hence, Numbers are $\sqrt{10}$ and 1 .
Where, 1 is a rational number and $\sqrt{10}$ is an irrational number.