Let $a \in Z$ and $b$ be its inverse
$\therefore a^* b=e=b^* a \\$
$\Rightarrow a+b-15=15=b+a-15 \\$
$\Rightarrow b=30-a \in Z \\$
$\therefore \text { The inverse of } a \in Z \text { is } 30-a$
$\mathrm{a}^* \mathrm{~b}=2^{5 \mathrm{ab}} ; \mathrm{a}, \mathrm{b} \in \mathrm{N}$