A projectile is given an initial velocity of $\hat{i}+2 \hat{j}$. The cartesian equation of its path is —
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A projectile is given an initial velocity of $\hat{i}+2 \hat{j}$. The cartesian equation of its path is $\left(g=10 m / s ^{2}\right)$

(a) $y=2 x-5 x^{2}$

(b) $y=x-5 x^{2}$

(c) $4 y=2 x-5 x^{2}$

(d) $y=2 x-25 x^{2}$

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The cartesian equation of its path will be $y=2 x-5 x^{2}$. So, The correct option of this question is (A).

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