Question

The value of integral $\int_{-1}^1 \frac{|x+2|}{x+2} d x$

(a) 1

(b) 2

(c) 0

(d) -1

Answer 1

SOLUTION — For $-1<x<1,|x+2|=2+x$

$\therefore \quad I=\int_{-1}^1\left(\frac{x+2}{x+2}\right) d x=\int_{-1}^1 1 d x=[x]_{-1}^1=2$

So, The correct option of this question will be (B).