SOLUTION :
Equation of any plane through given line is $a(x-1)+b(y+2)+c(z-3)=0$
Also, passing through $(4,3,7)$
$\therefore 3 a+5 b+4 c=0$
and $5 a+6 b+4 c=0$
$\therefore \frac{a}{-4}=\frac{b}{8}=\frac{c}{-7}$
$\Rightarrow \frac{a}{4}=\frac{b}{-8}=\frac{c}{7}$
$\therefore$ Required equation is
$4 x-8 y+7 z=41$
So, The correct option of this question will be (B).