Let $f(x)=x(2-x), 0 \leq x \leq 2$. If the definition of ' $f$ ' is extended over the set, $R-[0,2]$ by $f(x-2)=f(x)$, then prove that ' $f$ ' is a periodic function of period 2 .
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Let $f(x)=x(2-x), 0 \leq x \leq 2$. If the definition of ' $f$ ' is extended over the set, $R-[0,2]$ by $f(x-2)=f(x)$, then prove that ' $f$ ' is a periodic function of period 2 .

Let $f(x)=x(2-x), 0 \leq x \leq 2$. If the definition of ' $f$ ' is extended over the set, $R-[0,2]$ by $f(x-2)=f(x)$, then prove that ' $f$ ' is a periodic function of period 2 .
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Let $f(x)=x(2-x), 0 \leq x \leq 2$. If the definition of ' $f$ ' is extended over the set, $R-[0,2]$ by $f(x-2)=f(x)$, then prove that ' $f$ ' is a periodic function of period 2 .
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SOLUTION : $y=f(x+2)$ is drawn by shifting the graph by 2 units horizontally. 

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