SOLUTION :
We know that $c=v \lambda$;
where $c=$ velocity of radiation $=3 \cdot 0 \times 10^{10} cm / s$
$\therefore \quad v=\frac{c}{\lambda}=\frac{3 \cdot 0 \times 10^{10} cm / s }{5 \cdot 0 \times 10^{-4} cm }=6 \cdot 0 \times 10^{13} s ^{-1}= 6 \cdot 0 \times 10^{13} H z .$