Amongst H2O, H2S, H2Se and H2Te, the one with the highest boiling point is
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Amongst $\mathrm{H}_2 \mathrm{O}, \mathrm{H}_2 \mathrm{~S}, \mathrm{H}_2 \mathrm{Se}$ and $\mathrm{H}_2 \mathrm{Te}$, the one with the highest boiling point is

(A) $\mathrm{H}_2 \mathrm{O}$ because of hydrogen bonding

(B) $\mathrm{H}_2$ Te because of higher molecular weight

(C) $\mathrm{H}_2 \mathrm{~S}$ because of hydrogen bonding

(D) $\mathrm{H}_2 \mathrm{Se}$ because of lower molecular weight

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Best answer

$\mathrm{H}_2 \mathrm{O}$ has the highest boiling point due to $\mathrm{H}$-bonding. So, The correct option is (A).

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