SOLUTION : $f:[-1,1] \rightarrow[-1,1]$
(i) $f(x)=x-\sin x \quad \text { (odd function) } \\$
$f^{\prime}(x)=1-\cos x \geq 0 \text { increasing function }$
Hence one - one
$f(-1)=-1+\sin 1 \\$
$f(1)=1-\sin 1$
Range $\equiv[-1+\sin 1,1-\sin 1]$
$\neq$ co domain function is not bijecive
(ii) $\quad f(x)=x|x|=\left\{\begin{array}{cc}x^2, & x \geq 0 \\ -x^2, & x<0\end{array}\right.$
one - one function
Range $\equiv[-1,1]=$ codomain
$\therefore \quad$ onto function
(iii) $f(x)=\tan \left(\frac{\pi x}{4}\right)$
by graph one-one onto
Bijective function
(iv) $f(x)=x^4$ even function
many-one $\Rightarrow \quad$ Not bijective