Question

Which of the electronic configurations given below would you expect to have the lowest ionization energy?

(a) $1 s^{2} 2 s^{2} 2 p^{0} 3 s^{2}$

(b) $1 s^{2} 2 s^{2} 2 p^{6} 3 s^{1}$

(c) $1 s^{2} 2 s^{2} 2 p^{6}$

(d) $1 s^{2} 2 s^{2} 2 p^{5}$

Answer 1

ANSWER : Here, The correct answer of this question will be option (B) which is — $1 s^{2} 2 s^{2} 2 p^{6} 3 s^{1}$.