The equation $\frac{x^2}{10-a}+\frac{y^2}{4-a}=1$ represents an ellipse, if
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The equation $\frac{x^2}{10-a}+\frac{y^2}{4-a}=1$ represents an ellipse, if

The equation $\frac{x^2}{10-a}+\frac{y^2}{4-a}=1$ represents an ellipse, if
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The equation $\frac{x^2}{10-a}+\frac{y^2}{4-a}=1$ represents an ellipse, if

(a) $a<4$

(b) $a>4$

(c) $4<a<10$

(d) $a>10$

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SOLUTION —

For represent an ellipse, $10-a>0$ and $4-a>0$

$\Rightarrow \quad a<10$ and $a<4 \Rightarrow a<4$

So, The correct option of this question will be (A).

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