You are given the following cell at 298K, $Zn \left| Zn^{++} _{( aq .)}\right|| HCl ( aq .)|\left| H _{2}( g )\right| Pt$ with $E _{\text {cell }}=0.701 V$ and $E _{ Zn ^{2+} / Zn }^{0}=-0.76 V$.
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You are given the following cell at $298 K , Zn \left| Zn^{++} _{( aq .)}\right|| HCl ( aq .)|\left| H _{2}( g )\right| Pt$ with $E _{\text {cell }}=0.701 V$ and $E _{ Zn ^{2+} / Zn }^{0}=-0.76 V$. Which of the following amounts of NaOH (equivalent weight = 40) will just make the pH of cathodic compartment to be equal to 7.0 :

(A) 0.4 grams

(B) 4 grams

(C) 10 grams

(D) 2 grams

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Best answer

0.4 grams of NaOH will just make the pH of cathodic compartment to be equal to 7.0. So, The correct option of this question is (A).

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