The specific conductivity of an aqueous solution of a weak monoprotic acid is $0.00033$ ohm $^{-1} cm ^{-1}$ at a concentration $0.02 M$.
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The specific conductivity of an aqueous solution of a weak monoprotic acid is $0.00033$ ohm $^{-1} cm ^{-1}$ at a concentration $0.02 M$.

If at this concentration the degree of dissociation is $0.043$, then calculate the value of $\Lambda_{0}$ (in $ohm ^{-1} cm ^{2}$/leqt) :

(A) 483

(B) 438

(C) 348

(D) 384

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The value of \(\Lambda_{0}\) will be 384. So, The correct option of this question is (D).

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