The specific conductivity of an aqueous solution of a weak monoprotic acid is $0.00033$ ohm $^{-1} cm ^{-1}$ at a concentration $0.02 M$.
If at this concentration the degree of dissociation is $0.043$, then calculate the value of $\Lambda_{0}$ (in $ohm ^{-1} cm ^{2}$/leqt) :
(A) 483
(B) 438
(C) 348
(D) 384