The oxides of two metals $X$ and $Y$ are isomorphous. The metal $X$ whose atomic weight is 52 forms a chloride whose vapour density is 79. The oxide of $Y$ contains $47 \cdot 1 \%$ of exygen. Calculate atomic weight of $Y$.

### 0 Comments

## 1 Answer

**SOLUTION :**

Last portion of the problem gives eq. wt. of $Y$ and also from volatile chloride method valency of metal $X$ is found out, hence also the valency of $Y$ as the oxides of $X$ and $Y$ are isomorphous.

Wt. of oxygen $=47 \cdot 1 g$ and wt. of $Y=(100-47 \cdot 1) g =52 \cdot 9 g$

$\therefore \quad$ Eq. wt. of $Y=\frac{52 \cdot 9}{47 \cdot 1} \times 8=8 \cdot 98$

Let the valency of metal $X$ be $n$, hence formula of chloride of $X=X C l_{n}$.

Its vapour density $($ given $)=79, \therefore$ Mol. wt. $=2 \times$ V.D. $=79 \times 2=158$

From formula, mol. wt. of $X C l_{n}=$ at. wt. $X+n \times 35 \cdot 5=52+35 \cdot 5 n$

$\therefore \quad 52+35 \cdot 5 n=158, \quad \therefore 35 \cdot 5 n=158-52=106, \quad \therefore \quad n=\frac{106}{35 \cdot 5} \approx 3$

$\therefore$ Also valency of $Y=3$.

Atomic wt. of $Y=$ eq. wt. $\times$ valency $=8 \cdot 98 \times 3=26 \cdot 94$.

### 0 Comments

## RELATED DOUBTS

If You Have Any Query/Suggestion Regarding This Website or Post, Please Contact Us On : [email protected]

## CATEGORIES

- ALL CATEGORIES
- GENERAL KNOWLEDGE (3.9k)
- CURRENT AFFAIRS (367)
- HINDI (2.3k)
- SCIENCE (7.6k)
- SOCIAL SCIENCE (10.3k)
- MATHEMATICS (1.5k)
- TECHNOLOGY (685)
- HINDI MEANING (204)
- ABBREVIATION (139)
- ENGLISH (438)
- DEFINITION (77)
- COUNTRY (185)
- COMPANY (26)
- EDUCATION (198)
- ENTERTAINMENT (22)
- ART AND CULTURE (209)
- SPORTS (27)
- OTHERS (272)