Two elements X (at. mass =16) and Y (at. mass =14) combine to form compounds A, B and C. The ratio of different masses of Y which combines with a fixed mass of X in A, B and C is 1: 3: 5.
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Two elements $X($ at. mass $=16)$ and $Y($ at. mass $=14)$ combine to form compounds $A, B$ and $C$. The ratio of different masses of $Y$ which combines with a fixed mass of $X$ in $A, B$ and $C$ is $1: 3: 5$. If 32 parts by mass of $X$ combines with 84 parts by mass of $Y$ in $B$, then in $C, 16$ parts by mass of $X$ will combine with :

(A) 126 parts by mass of $Y$

(B) 42 parts by mass of $Y$

(C) 70 parts by mass of $Y$

(D) $25.2$ parts by mass of $Y$

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In C, 16 parts by mass of X will combine with 70 parts by mass of Y. So, The correct option of this question is will be (C).

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