SOLUTION : $E_{3}=E_{1}+E_{2}$ (by definition)
Here
$h v_{3}=h v_{1}+h v_{2}$
Further $\frac{h c}{\lambda_{3}}=\frac{h c}{\lambda_{1}}+\frac{h c}{\lambda_{2}}$
or, $\quad \frac{1}{\lambda_{3}}=\frac{1}{\lambda_{1}}+\frac{1}{\lambda_{2}}$
$\therefore \quad \lambda_{3}=\frac{\lambda_{1} \lambda_{2}}{\lambda_{1}+\lambda_{2}}$