SOLUTION : The mass of $H _{2}$ molecule is in five significant figures, i.e, error in the mass $=0.0001 \times 10^{-24} g$. Since the velocity is given to two significant figures,
we may assume that the error in the velocity is $0.1 \times 10^{8} cms ^{-1}$.
The error in the momentum is approximately equal to $\Delta p=1 \times 10^{-28} \times 0 \cdot 1 \times 10^{8}=1 \cdot 0 \times 10^{-21}$
$\Delta x=\frac{h}{4 \pi \times \Delta p}=\frac{6 \cdot 626 \times 10^{-27}}{4 \times 3 \cdot 1416 \times 1 \cdot 0 \times 10^{-21}}=5 \cdot 27 \times 10^{-7} c m \text {. }$