Question

Calculate the momentum of a photon whose frequency is $6.00 \times 10^{14} s ^{-1}$.

Answer 1

$\quad \lambda=\frac{h}{p}$, or, $p=\frac{h}{\lambda}$, and $c=v \lambda, \frac{1}{\lambda}=\frac{v}{c}$

$\therefore \quad p=\frac{h v}{c}=\frac{6 \cdot 626 \times 10^{-27} \times 6 \cdot 0 \times 10^{14}}{3 \cdot 0 \times 10^{10}}$

$=1 \cdot 325 \times 10^{-23} g cm / s .$