If A is the set of the divisors of the number 15, B is set of prime numbers smaller than 10 and C is the set of even numbers smaller than 9 , then $(A \cup C) \cap B$ is the set
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If $A$ is the set of the divisors of the number $15, B$ is set of prime numbers smaller than 10 and $C$ is the set of even numbers smaller than 9 , then $(A \cup C) \cap B$ is the set

(A) $\{1,3,5\}$

(B) $\{1,2,3\}$

(C) $\{2,3,5\}$

(D) $\{2,5\}$

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Best answer

Solution :

$\therefore A=\{1,3,5,15\}, B=\{2,3,5,7\}$ and $C=\{2,4,6,8\}$

$\begin{aligned} \therefore \quad(A \cup C) \cap B & =\{1,2,3,4,5,6,8,15\} \cap\{2,3,5,7\} \\ & =\{2,3,5\}\end{aligned}$

So, The Correct Option is (C).

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