In a reaction A (g) + 2 B (g) $\rightleftharpoons$ 2 C (g), 2 moles of ' $A ^{\prime}, 3$ moles of 'B' and 1 mole of 'C' are placed in a 2 L flask and the equilibrium concentration of 'C' is 1 mol / L.
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In a reaction $A( g )+2 B ( g ) \rightleftharpoons 2 C ( g ), 2$ moles of ' $A ^{\prime}, 3$ moles of ' $B$ ' and 1 mole of ' $C ^{\text {' }}$ are placed in a $2 L$ flask and the equilibrium concentration of ' $C$ ' is 1 mol / L. The equilibrium constant $\left( K _{ C }\right)$ for the reaction is :

(A) $0.33$ lit/mol

(B) $1.33$ lit/mol

(C) $1.66$ lit/mol

(D) $0.66$ lit/mol

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The equilibrium constant $\left( K _{ C }\right)$ for the above reaction will be $1.33$ lit/mol. So, The correct option of this question is (B).

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