SOLUTION : $x<y, y<z \quad \Rightarrow \quad x<z \forall x, y, z \in N$
$\therefore \quad x R y, y R z \quad \Rightarrow \quad x R z, \quad \therefore \text { Relation is transitive, } $
$\therefore \quad x<y \text { does not give } y<x .$
$\text { Relation is not symmetric. }$
$\text { Since } x<x \text { does not hold, hence relation is not reflexive. }$
