If $f: R \rightarrow R$ is defined by $f(x)=x^2-3 x+2$, find $f(f(x))$.
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If $f: R \rightarrow R$ is defined by $f(x)=x^2-3 x+2$, find $f(f(x))$.

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SOLUTION : $f(f(x))  =f\left(x^2-3 x+2\right)=\left(x^2-3 x+2\right)^2-3\left(x^2-3 x+2\right)+2 \\$

$ =x^4+9 x^2+4-6 x^3-12 x+4 x^2-3 x^2+9 x-6+2=x^4-6 x^3+10 x^2-3 x$

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