The set of values of a for which the point (a-1, a+1) lies outside the circle x2 + y2 = 8 and inside the circle $x^{2}+y^{2}-12 x+12 y-62=0$ is
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The set of values of a for which the point $(a-1, a+1)$ lies outside the circle $x^{2}+y^{2}=8$ and inside the circle $x^{2}+y^{2}-12 x+12 y-62=0$ is

(1) $(\sqrt{3}, 3 \sqrt{2}) \cup(-\infty, 0)$

(2) $(-3 \sqrt{2},-\sqrt{3}) \cup(\sqrt{3}, 3 \sqrt{2})$

(3) $(-3 \sqrt{2},-\sqrt{3}) \cup(0, \infty)$

(4) None of these

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ANSWER : The correct option of this question will be (2).

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