Equation of median through vertex B of △ABC where $A(0,0), B(0,1) \& C(1,0)$ is

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If $A=\left[\begin{array}{rrr}1 & 2 & -1 \\ 3 & 0 & 2 \\ 4 & 5 & 0\end{array}\right], B=\left[\begin{array}{lll}1 & 0 & 0 \\ 2 & 1 & 0 \\ 0 & 1 & 3\end{array}\right]$, then AB is

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If $A=\left[\begin{array}{rr}-1 & 2 \\ 2 & -1\end{array}\right]$ and $B=\left[\begin{array}{l}3 \\ 1\end{array}\right]$, AX=B, then X is equal to

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$\left|\begin{array}{lll}1 & a & a^2-b c \\ 1 & b & b^2-a c \\ 1 & c & c^2-a b\end{array}\right|$ is equal to

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If the median of x/5, x, x/4, x/2 and x/3, where x>0, is 8 then the value of x is equal to

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If $A=\left[\begin{array}{rr}r & -2 \\ 3 & 7\end{array}\right]$ and $A^{-1}=\left[\begin{array}{cc}\frac{7}{34} & \frac{1}{17} \\ \frac{-3}{34} & \frac{2}{17}\end{array}\right]$, then the value of x is

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यदि $A=\{a, b, c\}, B=\{1,2,3\}$ और $f=\{(a, 1),(b, 2),(c, 2)\}$ तो $f$ कैसा फलन है?

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Let * be a binary operation on Z × Z defined by $(a, b)^*(c, d)=(a+c, b+d) ;(a, b),(c, d) \in Z \times Z$. Find $(1,2) *(3,5)$ and $(4,3) *(1,0)$.

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Let A={1,2,3,4,5,6} and * be an operation A defined by $a{ }^* b=r$, where r is the least non-negative remainder when the product a b is divided by k. Operation * is binary operation if k=

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Given a binary operation $: A \times A \rightarrow A$ with the identity element $e$ in $A$, an element $a \in A$ is said to be invertible with respect to the operation * if there exists an element $b$ in A such that $a^* b=e=b^* a$ and $b$ is called the inverse of $a$ and is denoted by ${a}^{-1}$.

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Equation of median through vertex B of △ABC where $A(0,0), B(0,1) \& C(1,0)$ is

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