If $A\left(\cos \theta_{1}, \sin \theta_{1}\right) B\left(\cos \theta_{2}, \sin \theta_{2}\right) \& C\left(\cos \theta_{3}, \sin \theta_{3}\right)$, then orthocenter of $\triangle A B C$ is
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If $A\left(\cos \theta_{1}, \sin \theta_{1}\right),B\left(\cos \theta_{2}, \sin \theta_{2}\right) \& C\left(\cos \theta_{3}, \sin \theta_{3}\right)$, then orthocenter of $\triangle A B C$ is

(1) $\left(\frac{\Sigma \cos \theta_{1}}{2}, \frac{\Sigma \sin \theta_{1}}{2}\right)$

(2) $\left(\frac{\Sigma \cos \theta_{1}}{3}, \frac{\Sigma \sin \theta_{1}}{3}\right)$

(3) $\left(\Sigma \cos \theta_{1}, \Sigma \sin \theta_{1}\right)$

(4) Data insufficient

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ANSWER : The correct answer of this question is option (3).

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