To estimate ' $g$ ' (from $g=4 \pi^{2} \frac{L}{T^{2}}$ ), error in measurement of $L$ is $\pm 2 \%$ and error in measurement of $T$ is $\pm 3 \%$. The error in estimated ' $g$ ' will be -
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To estimate ' $g$ ' (from $g=4 \pi^{2} \frac{L}{T^{2}}$ ), error in measurement of $L$ is $\pm 2 \%$ and error in measurement of $T$ is $\pm 3 \%$.

The error in estimated ' $g$ ' will be -

(1) $\pm 8 \%$

(2) $\pm 6 \%$

(3) $\pm 3 \%$

(4) $\pm 5 \%$

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Best answer

The error in estimated ' g ' will be ±8%. So, The correct option of this question is (1).

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