SOLUTION —
$\begin{array}{l}x^4+y^4=t^2+\frac{1}{t^2}=\left(t+\frac{1}{t}\right)^2-2 \\=\left(x^2+y^2\right)^2-2 \\\Rightarrow \quad x^4+y^4=x^4+y^4+2 x^2 y^2-2 \\\Rightarrow \quad x^2 y^2=1 \\\Rightarrow \quad 2 x \cdot y^2+2 x^2 y \frac{d y}{d x}=0 \\\Rightarrow \quad \frac{d y}{d x}=-\frac{y}{x} \\\end{array}$
So, The correct option will be (B).