A student performs an experiment for determination of $g\left(=\frac{4 \pi^{2} \ell}{ T ^{2}}\right), \ell \approx 1 m$, and he commits an error of $\Delta \ell$.
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 A student performs an experiment for determination of $g\left(=\frac{4 \pi^{2} \ell}{ T ^{2}}\right), \ell \approx 1 m$, and he commits an error of $\Delta \ell$.

For $T$ he takes the time of $n$ oscillations with the stop watch of least count $\Delta T$ and he commits a human error of $0.1 sec$. For which of the following data, the measurement of $g$ will be most accurate?

(1) $\Delta L =0.5, \Delta T =0.1, n =20$

(2) $\Delta L =0.5, \Delta T =0.1, n =50$

(3) $\Delta L =0.5, \Delta T =0.01, n =20$

(4) $\Delta L =0.1, \Delta T =0.05, n =50$

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Ans : $\triangle L$ = 0.1, $\triangle T$ = 0.05, n = 50.

So, The correct option of this question will be (4)

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