SOLUTION —
Now, $\mathbf{d}=(3-1) \mathbf{i}+(4-2) \mathbf{j}+(5-3) \mathbf{k}=2 \mathbf{i}+2 \mathbf{j}+2 \mathbf{k}$
$\therefore$ Work done $=\mathbf{F} \cdot \mathbf{d}=(2 \mathbf{i}-3 \mathbf{j}+2 \mathbf{k}) \cdot(2 \mathbf{i}+2 \mathbf{j}+2 \mathbf{k})$ $=2$ units
So, The correct option of this question will be (A).