Let $R=\{(x, y): x, y \in A, x+y=5\}$ where A={1,2,3,4,5} then prove that R is neither reflexive nor transitive but symmetric.
Register

Let $R=\{(x, y): x, y \in A, x+y=5\}$ where A={1,2,3,4,5} then prove that R is neither reflexive nor transitive but symmetric.

Let $R=\{(x, y): x, y \in A, x+y=5\}$ where A={1,2,3,4,5} then prove that R is neither reflexive nor transitive but symmetric.
54 views
0 Votes
0 Votes
Let $R=\{(x, y): x, y \in A, x+y=5\}$ where $A=\{1,2,3,4,5\}$ then prove that $R$ is neither reflexive nor transitive but symmetric.
User Avatar
by

1 Answer

0 Votes
0 Votes
 
Best answer
$R=\{(x, y) ; x, y \in A, x+y=5\} $

$\quad A=\{1,2,3,4,5\}$

$R=\{(1,4),(2,3),(3,2),(4,1)\}$

$\mathrm{R}$ is symmetric but neither reflexive nor transitive.
User Avatar
by

RELATED DOUBTS

User Avatar
Chandan Asked Sep 12, 2023
59 views
Show that the relation R in R defined as $R=\{(a, b): a \leq b\}$ is not symmetric.
Chandan Asked Sep 12, 2023
by Chandan
1 Answer
0 Votes
0 Votes
59 Views
ASK DOUBTS
Peddia is an Online Question and Answer Website, That Helps You To Prepare India's All States Boards & Competitive Exams Like IIT-JEE, NEET, AIIMS, AIPMT, SSC, BANKING, BSEB, UP Board, RBSE, HPBOSE, MPBSE, CBSE & Other General Exams.
If You Have Any Query/Suggestion Regarding This Website or Post, Please Contact Us On : [email protected]

CATEGORIES

POPULAR TAGS
©2023 - ALL RIGHTS RESERVED BY PEDDIA
Link Copied!