Question

Let $P=\left\{(x, y) \mid x^2+y^2=1, x, y \in R\right\}$, then $P$ is

(A) reflexive

(B) symmetric

(C) transitive

(D) equivalence

Answer 1

SOLUTION : Obviously, The relation $P$ is neither reflexive nor transitive but it is symmetric, Because $x^2+y^2=1 \Rightarrow y^2+x^2=1$.

Above Correct Answer is Option B.