Equation of chord of minimum length passing through (1, 2) of circle $x^{2}+y^{2}-4 x-2 y-4=0$ is ax + by + c = 0 then a+b+c=
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Equation of chord of minimum length passing through (1, 2) of circle $x^{2}+y^{2}-4 x-2 y-4=0$ is ax + by + c = 0 then a+b+c=

Equation of chord of minimum length passing through (1, 2) of circle $x^{2}+y^{2}-4 x-2 y-4=0$ is ax + by + c = 0 then a+b+c=
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Equation of chord of minimum length passing through $(1,2)$ of circle $x^{2}+y^{2}-4 x-2 y-4=0$ is $a x+b y+c=0$ then $a+b+c=$

(1) 8

(2) $-8$

$(3) \pm 8$

(4) None of these

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Ans : The correct option of this question will be (3).

SOLUTION / HINT :

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