Question

Two faraday's of electricity are passed through a solution of ${CuSO}_4$. The mass of copper deposited at the cathode is (at. mass of ${Cu}=63.5 {amu}$ )

(a) $2 {g}$

(b) $127 {g}$

(c) $0 {g}$

(d) $63.5 {g}$

Answer 1

Correct Option : (D)

Explanation —

${Cu}^{2+}+2 e^{-} \longrightarrow {Cu}$

$2 {F}$ charge deposit $1 {mol}$ of ${Cu}$ i.e., $2 {F}$ of electricity deposit $63.5 {g}$ mass of ${Cu}$ at the cathode.