An aqueous solution of 6.3 g oxalic acid dihydrate is made up to 250 mL. The volume of 0.1 N NaOH required to completely neutralize 10 mL of this solution is

Question

An aqueous solution of $6.3 \mathrm{~g}$ oxalic acid dihydrate is made up to $250 \mathrm{~mL}$. The volume of $0.1 \mathrm{~N} \mathrm{NaOH}$ required to completely neutralize $10 \mathrm{~mL}$ of this solution is

(A) $40 \mathrm{~mL}$

(B) $20 \mathrm{~mL}$

(C) $10 \mathrm{~mL}$

(D) $4 \mathrm{~mL}$

Answer 1

$\begin{array}{l}\text {Normality of oxalic acid }=\frac{6.3 \times 1000}{63 \times 250}=0.4 \mathrm{~N} \\N_1 V_1=N_2 V_2 \text { or } 0.1 \times V_1=0.4 \times 10 \\\therefore \quad V_1=40 \mathrm{~mL}\end{array}$

So, The correct option is (A).