SOLUTION —
On differentiating, w.r.t. $t$, we get
$\begin{aligned}\frac{d x}{d t} & =\cos t, \frac{d y}{d t}=-2 \sin 2 t \\\therefore \quad \frac{d y}{d x} & =\frac{d y / d t}{d x / d t}=\frac{-2 \sin 2 t}{\cos t} \\& =-4 \sin t\end{aligned}$
So, The correct option will be (B).