SOLUTION —
$f(x)=\log _x\left(\log _e x\right)=\frac{\log _e \log _e x}{\log _e x}$
$\begin{aligned}\Rightarrow \quad f^{\prime}(x) & =\frac{\log _e x \cdot \frac{1}{\log _e x} \cdot \frac{1}{x}-\log _e \log _e x \cdot \frac{1}{x}}{\left(\log _e x\right)^2} \\\Rightarrow \quad f^{\prime}(x) & =\frac{1-\log _e \log _e x}{x\left(\log _e x\right)^2} \\\Rightarrow \quad f^{\prime}(e) & =\frac{1-\log _e \log _e e}{e\left(\log _e e\right)^2} \\& =\frac{1-\log _e 1}{e}=\frac{1}{e}\end{aligned}$
So, The correct option will be (D).