SOLUTION —
$\lim _{x \rightarrow 0} \frac{(1-\cos 2 x) \sin 5 x}{x^2 \sin 3 x}$
$\begin{array}{l}=\lim _{x \rightarrow 0} \frac{1-\cos 2 x}{x^2} \times \frac{\sin 5 x}{5 \cdot \frac{x}{5}} \times \frac{3 x}{3 \sin 3 x} \\=\lim _{x \rightarrow 0} \frac{2 \sin ^2 x}{x^2} \times 5 \times \frac{1}{3}=\frac{10}{3} \quad\left(\because \lim _{x \rightarrow 0} \frac{\sin x}{x}=1\right)\end{array}$
So, The correct option will be (A).