SOLUTION —
$\lim _{x \rightarrow 0} \frac{\tan x-\sin x}{x^3}$
$\begin{array}{l}=\lim _{x \rightarrow 0} \frac{\tan x(1-\cos x)}{x^3} \\=\lim _{x \rightarrow 0} \frac{\tan x}{x} \cdot \frac{2 \sin ^2(x / 2)}{4 \cdot(x / 2)^2}=\frac{1}{2}\end{array}$
So, The correct option will be (C).