The value of $\lim _{x \rightarrow 7}\left(\frac{2-\sqrt{x-3}}{x^2-49}\right)$ is
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The value of $\lim _{x \rightarrow 7}\left(\frac{2-\sqrt{x-3}}{x^2-49}\right)$ is

(A) $2 / 9$

(B) $-2 / 49$

(C) $-1 / 56$

(D) $-1 / 59$

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Best answer

The correct option will be (C).

HINT —

$\lim _{x \rightarrow 7}\left(\frac{2-\sqrt{x-3}}{x^2-49}\right) \quad\left(\frac{0}{0}\right.$ form $)$

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