40 mL of a mixture of CO and H2 yielded 15 mL of CO2 after explosion with an excess of O2. The percentage of CO in the mixture would be:
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40 mL of a mixture of CO and H2 yielded 15 mL of CO2 after explosion with an excess of O2. The percentage of CO in the mixture would be:

40 mL of a mixture of CO and H2 yielded 15 mL of CO2 after explosion with an excess of O2. The percentage of CO in the mixture would be:
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40 mL of a mixture of $CO$ and $H_2$ yielded 15 mL of $CO_2$ after explosion with an excess of $O_2$.  The percentage of $CO$ in the mixture would be:

(A) 30%

(B) 35%

(C) 37.5%

(D) 42.5%

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Ans : The percentage of CO in the mixture would be 37.5%. So, The correct answer of this question will be option (C).

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