SOLUTION : $\quad 2 CO ( g )+ O _{2}( g )=2 CO _{2}( g )$
$\begin{array}{ll}2 \text { vol } & 2 \text { vol. } \\ 100 mL & 100 mL \end{array}$
Since the same vol. of $CO _{2}$ is formed from the same volume of $CO$, hence the volume of $CO _{2}$ formed at $127^{\circ} C$ and $725 mm$ pressure (according to Gay-Lussac's law) from 100.
Now,
By ideal gas cquation, $\frac{P_{1} V_{1}}{T_{1}}=\frac{P_{2} V_{2}}{T_{2}}$
$\therefore \quad V_{2}=\frac{P_{1} V_{1}}{T_{1}} \times \frac{T_{2}}{P_{2}}=\frac{725 \times 100}{400} \times \frac{300}{700} mL =77 \cdot 7 mL \text {. }$