Volume of H2 evolved at STP on complete reaction of 27g of aluminum with excess of aqueous NaOH would be:

Question

Volume of $H _{2}$ evolved at STP on complete reaction of $27 g$ of aluminium with excess of aqueous $NaOH$ would be:

$Al + NaOH + H _{2} O \longrightarrow$ Sodium meta aluminate $+ H _{2}$

(A) $22.4$ litres

(B) $44.8$ litres

(C) $67.2$ litres

(D) $33.6$ litres

Answer 1

Volume of $H _{2}$ evolved at STP on complete reaction of $27 g$ of aluminum with excess of aqueous $NaOH$ would be 33.6 litres. So, The correct option of this question is (D).