Haemoglobin contains 0.25 % iron by weight. The molecular weight of Hemoglobin is 89600 u. Calculate the weight of K4[ Fe (CN)_{6}] that can be produced

Question

Hemoglobin contains $0.25 \%$ iron by weight. The molecular weight of Hemoglobin is $89600 u$. Calculate the weight of $K _{4}\left[ Fe ( CN )_{6}\right]$ that can be produced, if all the iron atoms from $4.48 kg$ Hemoglobin are converted into $K _{4}\left[ Fe ( CN )_{6}\right]$ through a series of reactions.

Answer 1

The weight of $K _{4}\left[ Fe ( CN )_{6}\right]$ will be 73.6 g that can be produced, if all the iron atoms from $4.48 kg$ Hemoglobin are converted into $K _{4}\left[ Fe ( CN )_{6}\right]$ through a series of reactions.