A gaseous mixture contains three gases A, B and C with a total number of moles of 10 and total pressure of 10 atm.
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A gaseous mixture contains three gases $A, B$ and $C$ with a total number of moles of 10 and total pressure of $10 atm$. The partial pressure of $A$ and $B$ are $3 atm$ and $1 atm$ respectively and if $C$ has molecular weight of $2 g / mol$. Then, the weight of $C$ present in the mixture will be:

(A) $8 g$

(B) $12 g$

(C) $3 g$

(D) $6 g$

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The weight of C present in the mixture will be 12 g. So, The correct option of this question is (B).

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