The number of moles of Phosphoric acid H3PO4 that can be produced, by allowing 0.8 moles of H2, 0.9 moles of P4 and 1 mole of O2 to combine according to the given unbalanced reaction, is :

Question

The number of moles of Phosphoric acid $\left( H _{3} PO _{4}\right)$ that can be produced, by allowing $0.8$ moles of $H _{2}, 0.9$ moles of $P _{4}$ and 1 mole of $O _{2}$ to combine according to the given unbalanced reaction, is :

$H _{2}+ P _{4}+ O _{2} \longrightarrow H _{3} PO _{4}$

(A) $0.533$ mole

(B) $3.6$ mole

(C) $0.5$ mole

(D) $1.2$ mole

Answer 1

The number of moles of Phosphoric acid $\left( H _{3} PO _{4}\right)$ that can be produced, by allowing $0.8$ moles of $H _{2}, 0.9$ moles of $P _{4}$ and 1 mole of $O _{2}$ to combine according to the given unbalanced reaction, is 0.5 mole.

So, The correct option of this question is (C).