300 ml of 3.0 M NaCl solution is added to 200 ml of 4.0 M BaCl2 solution. The concentration of Cl− ions in the resulting solution is —
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300 ml of 3.0 M NaCl solution is added to 200 ml of 4.0 M BaCl2 solution. The concentration of Cl− ions in the resulting solution is —

300 ml of 3.0 M NaCl solution is added to 200 ml of 4.0 M BaCl2 solution. The concentration of Cl− ions in the resulting solution is —
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300 ml of 3.0 M $NaCl$ solution is added to $200 ml$ of 4.0 M $BaCl _{2}$ solution. The concentration of $Cl ^{-}$ions in the resulting solution is

(A) $7 M$

(B) $6 M$

(C) $5.5 M$

(D) $5 M$

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The concentration of Cl– ions in the resulting solution is 5M. So, The correct option of this question is (D).

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