If V is the volume of one molecule of a gas, the van der Waals constant ' b ' is :
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If $V$ is the volume of one molecule of a gas, the van der Waals constant ' $b$ ' is :

(A) $\frac{4 V }{ N _{0}}$

(B) $4 V$

(C) $\frac{N_{0}}{4 V}$

(D) $4 VN _{0}$

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Best answer

If $V$ is the volume of one molecule of a gas, the van der Waals constant ' $b$ ' will be $4 VN _{0}$.

So, The correct option of this question is (D).

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