CH3-CO-CH3 (g) $\rightleftharpoons$ CH3-CH3 (g)+ CO (g) Initial pressure of CH3COCH3 is 100 mm. When equilibrium is set up, mole fraction of CO (g) is 1 / 3. Hence value of K_p for given reaction is :
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$CH _{3}- CO - CH _{3}( g ) \rightleftharpoons CH _{3}- CH _{3}( g )+ CO ( g )$

Initial pressure of $CH _{3} COCH _{3}$ is 100 mm. When equilibrium is set up, mole fraction of $CO ( g )$ is $1 / 3$. Hence value of $K_{p}$ for given reaction is :

(A) 100 mm

(B) 50 mm

(C) 25 mm

(D) 0.6 mm

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The value of $K_{p}$ for given reaction is will be 50 mm. So, The correct option of this question is (B).

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