25.4g of iodine and 14.2g of chlorine are made to react completely to yield a mixture of ICl and ICl3.

Question

$25.4 g$ of iodine and $14 \cdot 2 g$ of chlorine are made to react completely to yield a mixture of $ICl$ and $ICl _{3}$. Calculate the ratio of the moles of $ICI$ and $ICl _{3}$ formed. $(I=127, C l=35 \cdot 5)$

Answer 1

SOLUTION : Suppose that $x$ mole of $ICl$ and $y$ mole of $ICl _{3}$ are formed.

Total iodine $\quad: 127 x+127 y=25 \cdot 4$

Total chlorine : $35 \cdot 5 x+\frac{213 y}{2}=14 \cdot 2$

From (I), $\quad x+y=0 \cdot 2, \quad$ From (II), $\quad x+3 y=0 \cdot 4$

$\therefore \quad 2 y=0 \cdot 2 ; \quad y=0 \cdot 1, x=0 \cdot 1, \quad I C l: I C l_{3}=1: 1$.